Create an account

Very important

  • To access the important data of the forums, you must be active in each forum and especially in the leaks and database leaks section, send data and after sending the data and activity, data and important content will be opened and visible for you.
  • You will only see chat messages from people who are at or below your level.
  • More than 500,000 database leaks and millions of account leaks are waiting for you, so access and view with more activity.
  • Many important data are inactive and inaccessible for you, so open them with activity. (This will be done automatically)


Thread Rating:
  • 529 Vote(s) - 3.52 Average
  • 1
  • 2
  • 3
  • 4
  • 5
Arduino can't read Serial properly

#1
Alright, I've googled getting a string from Serial with Arduino and I've had no luck even copy and pasting examples.

I'm trying to get a string from the Serial. Here's my code:

void setup() {
Serial.begin(9600);
Serial.write("Power On");
}

void loop()
{
while(!Serial.available());

while (Serial.available() > 0) {
Serial.write(Serial.read());
}
Serial.println();
}

And it's printing out character by character.

I also tried

char* read(int len) {
while (!Serial.available());
char str[len];
int i = 0;
while (i < len) {
str[i] = '\0';
int inByte = Serial.read();
Serial.println(inByte);
if (inByte == -1) {
return str;
} else {
str[i++] = inByte;
}
}
return str;
}

And it returns 1 character at a time (serial.print(inByte) gives -1 every other time). Why is the Serial splitting each character?

If I enter 'hello' and I call serial.read() it gives a character then says there's nothing, then gives another character and says there's nothing.
Reply

#2
I don't have access to the Arduino source files here, but the following line of code won't give you a full String for obvious reasons (let me know if it's not that obvious):

int inByte = Serial.read();


Also, using

Serial.write()

you'll be sending byte per byte. That's the oposite from

Serial.println()

in which you'll be sending full sentences.

I would try working with Serial.print() or println() rather then Serial.write().

You can check out the references:

[To see links please register here]


[To see links please register here]

Reply

#3
It exists delay when transferring data via UART. Have a try with Serial.timedRead() instead. The code is as below.

void setup() {
Serial.begin(9600);
Serial.write("Power On");
}

void loop()
{
while(!Serial.available());

while (true) {
int byte = Serial.timedRead();
if(byte == -1)
break;
Serial.write(byte);
}
Serial.println();
}
Reply

#4
I figured it out.

When you open a Serial with 9600 baud (`Serial.begin(9600);`), it's reading/writing at 9600 bytes per second. That means at fastest it can get just under 10 bytes per millisecond. I don't know what the operating speed is, but it seems like the Arduino gets alerted of and reads the first byte before the second one arrives. So, you must add a `delay(1)` to "wait" for another byte in the "same stream" to arrive.

String read() {
while (!Serial.available()); //wait for user input
//there is something in the buffer now
String str = "";
while (Serial.available()) {
str += (char) Serial.read();
delay(1); //wait for the next byte, if after this nothing has arrived it means the text was not part of the same stream entered by the user
}
return str;
}

You may ask, well since you're delaying how do you know if the user is just typing very fast? You can't avoid it here, since the Serial is essentially limited at a certain speed. However, the user must be typing virtually-impossibly-fast for two inputs to be confused as one.
Reply

#5
Even though this post is old, I'll post my answer in case someone googles their way here.

For reading strings from the serial you can use the following:

String str;

while (Serial.available() > 0) {
str = Serial.readString();
}

Works like a charm!
Reply

#6
String str;

void setup()
{
Serial.begin(9600);
}

void loop ()
{
while (Serial.available() > 0){
char c = Serial.read();
str.concat©;
if (Serial.available() == 0)
{
Serial.print(str);
str = "";
break;
}
}
}
Reply

#7
I wrote this simple Serial full message repeater. It does not require a `String` object or any kind of delaying as in previous answers.

**How it works**<br>
It receives characters and stores them in buffer until terminating character `\n` or `\0` is received. Then it prints the whole buffer back.

There is also implemented buffer overflow check, so you don't lose any data.

The main advantage of this solution is the speed and possibility to react to the message content even before the whole reading procedure is complete (for example, you can implement a message parser on top of this very easily).

```
#define LENGTH 20

void setup() {
Serial.begin(9600);
Serial.println("Ready to read");
}

void loop() {
if (Serial.available()) {
char buffer[LENGTH];
int index = 0;
bool receiving = true;

while (receiving) {
if (Serial.available()) {
char ch = Serial.read();
if (ch == '\n' || ch == '\0') {
buffer[index] = '\0';
receiving = false;
} else {
buffer[index++] = ch;
if (index == LENGTH) {
buffer[index] = '\0';
break;
}
}
}
}

Serial.println(buffer);
}
}
```
Reply



Forum Jump:


Users browsing this thread:
1 Guest(s)

©0Day  2016 - 2023 | All Rights Reserved.  Made with    for the community. Connected through