How to convert an NSString into an NSNumber

You can just use `[string intValue]` or `[string floatValue]` or `[string doubleValue] ` etc

You can also use [`NSNumberFormatter`][1] class:

[1]:

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Thanks All! I am combined feedback and finally manage to convert from text input ( string ) to Integer. Plus it could tell me whether the input is integer :)

NSNumberFormatter * f = [[NSNumberFormatter alloc] init];
[f setNumberStyle:NSNumberFormatterDecimalStyle];
NSNumber * myNumber = [f numberFromString:thresholdInput.text];

int minThreshold = [myNumber intValue];

NSLog(@"Setting for minThreshold %i", minThreshold);

if ((int)minThreshold < 1 )
{
NSLog(@"Not a number");
}
else
{
NSLog(@"Setting for integer minThreshold %i", minThreshold);
}
[f release];

Worked in **Swift 3**

NSDecimalNumber(string: "Your string")

I know this is very late but below code is working for me.

Try this code

`NSNumber *number = @([dictionary[@"keyValue"] intValue]]);`

This may help you. Thanks

you can also do like this code 8.3.3 ios 10.3 support

[NSNumber numberWithInt:[@"put your string here" intValue]]

extension String {

var numberValue:NSNumber? {
let formatter = NumberFormatter()
formatter.numberStyle = .decimal
return formatter.number(from: self)
}
}

let someFloat = "12.34".numberValue

Try this

NSNumber *yourNumber = [NSNumber numberWithLongLong:[yourString longLongValue]];

Note - I have used longLongValue as per my requirement. You can also use integerValue, longValue, or any other format depending upon your requirement.

Use an `NSNumberFormatter`:

NSNumberFormatter *f = [[NSNumberFormatter alloc] init];
f.numberStyle = NSNumberFormatterDecimalStyle;
NSNumber *myNumber = [f numberFromString:@"42"];

If the string is not a valid number, then `myNumber` will be `nil`. If it is a valid number, then you now have all of the `NSNumber` goodness to figure out what kind of number it actually is.

Objective-C
==
(Note: this method doesn't play nice with difference locales, but is slightly faster than a `NSNumberFormatter`)

NSNumber *num1 = @([@"42" intValue]);
NSNumber *num2 = @([@"42.42" floatValue]);


___

Swift
==
**Simple but dirty way**

// Swift 1.2
if let intValue = "42".toInt() {
let number1 = NSNumber(integer:intValue)
}

// Swift 2.0
let number2 = Int("42")

// Swift 3.0
NSDecimalNumber(string: "42.42")

// Using NSNumber
let number3 = NSNumber(float:("42.42" as NSString).floatValue)


**The extension-way**
This is better, really, because it'll play nicely with locales and decimals.

extension String {

var numberValue:NSNumber? {
let formatter = NumberFormatter()
formatter.numberStyle = .decimal
return formatter.number(from: self)
}
}

Now you can simply do:

let someFloat = "42.42".numberValue
let someInt = "42".numberValue