Iterate through char array and print chars

I am trying to print each char in a variable.

I can print the ANSI char number by changing to this `printf("Value: %d\n", d[i]);` but am failing to actually print the string character itself.

What I am doing wrong here?

#include <stdio.h>
#include <string.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
int len = strlen(argv[1]);
char *d = malloc (strlen(argv[1])+1);
strcpy(d,argv[1]);

int i;
for(i=0;i<len;i++){
printf("Value: %s\n", (char)d[i]);
}
return 0;
}

You should use `%c` format to print characters in C. You are using `%s`, which requires to use pointer to the string, but in your case you are providing integer instead of pointer.

The below will work. You pass in the pointer to a string when using the token %s in printf.

#include <stdio.h>
#include <string.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
int len = strlen(argv[1]);
char *d = malloc (strlen(argv[1])+1);
strcpy(d,argv[1]);

printf("Value: %s\n", d);
return 0;
}