Mips: Computing the sum of two inputs

It seems very simple but I think my program won't compile because I'm overwriting the $v0 register? Thanks in advance

UPDATE:nevermind got it, my order was wrong when I made the syscall for printing the sum...
fixed in case anyone needs reference.


.data
prompt1: .asciiz "\n\n Enter the first integer please:"
prompt2: .asciiz "Enter the second integer please:"
result: .asciiz "The result is:"

.text

main:

#t0-to hold first integer
#t1-to hold second integer
#t2- used to hold the sum of t$1 and t$2

#first number

li $v0, 4 #syscall to print string
la $a0, prompt1 #address of string to print
syscall

li $v0, 5 #syscall to read an integer
syscall
move $t0, $v0 #move the number to read into $t0

#second number
li $v0, 4
la $a0, prompt2
syscall

li $v0,5
syscall
move $t1,$v0

add $t2, $t1, $t0 #compute the sum

#print out sum of $t2
li $v0, 4 # load syscall print int into $v0
move $a0, $t2 #move the number to print into $a0
li, $v0,1
la, $a0, result
syscall


Done:

li $v0, 10 #syscall to exit
syscall

.data
prompt1: .asciiz "\n\n Enter the first integer please:"
prompt2: .asciiz "Enter the second integer please:"
result: .asciiz "The result is:"

.text
main:
#t0-to hold first integer
#t1-to hold second integer
#t2- used to hold the sum of t$1 and t$2
#first number
li $v0, 4 #syscall to print string
la $a0, prompt1 #address of string to print
syscall
#
li $v0, 5 #syscall to read an integer
syscall
move $t0, $v0 #move the number to read into $t0
#second number
li $v0, 4
la $a0, prompt2
syscall
#
li $v0,5
syscall
move $t1,$v0
#
#print out sum of $t2
li $v0, 4
la $a0, result
syscall
#
add $a0, $t1, $t0 #compute the sum
li $v0, 1
syscall
#
li $v0, 10
syscall

Actually you messed up in this section:

` #print out sum of $t2
li $v0, 4 # load syscall print int into $v0
move $a0, $t2 #move the number to print into $a0
li, $v0,1
la, $a0, result
syscall`

Lets do it line by line:
`li $v0, 4 #You are ready to indicate that you want to print string`
`la $a0, result #you have loaded the address of string now`
`syscall # Now you will see: "The result is: `

Now lets print the number
`li $v0, 1`
`move $a0, $t2`
`syscall`

Footnote: Everytime you indicate you will use syscall, you should complete that command first.
for example, if you want to print something, you must complete syscall for that set and then move on to print integer.

example:
Lets say we want to print something like this,.
Number : 1

MIPS code would be:
` .data
prompt: .asciiz "Number : "
.text
main:
#Now lets read a number
li $v0, 5
syscall # -> note syscall is done for each instruction
#Lets complete printing first
li $v0, 4
la $a0, prompt
syscall`

#We have the number in $t0 right now
#if we do
`li $v0, 1
la $a0, prompt
syscall `
#ask question and answer yourself. what will be printed.
#the numbe we had entered or adress of prompt
#what do you need to modify here?

.text
main:
#print the msg1
li $v0 4
la $a0 msg1
syscall

#read the num 1
li $v0 5
syscall

sw $v0 a1

#print the msg2
li $v0 4
la $a0 msg2
syscall

#read the Num 2
li $v0 5
syscall

sw $v0 a2

#print the msg3
li $v0 4
la $a0 msg3
syscall

lw $t0 a1
lw $t1 a2


li $v0 1
add $a0 $t0 $t1
syscall
.data
msg1: .asciiz "Enter the first number :"
msg2: .asciiz "Enter the second number :"
a1 : .word 0
a2 : .word 0
msg3: .asciiz "The sum is = "