Node js Get folder path from a file

Is there a way to get the path to a folder that holds a particular file.

fs.realpathSync('config.json', []);

returns something like

G:\node-demos\7-node-module\demo\config.json

I just need

G:\node-demos\7-node-module\demo\
or
G:\node-demos\7-node-module\demo\
Is there any api for this or will I need to process the string?

`require("path").dirname(……)` **breaks** when your path does not explicitly specify its directory.

```javascript
require("path").dirname("./..")
// "."
```

-----

You may consider using `require("path").join(……, "../")` instead. It preserves the trailing separator as well.

```javascript
require("path").join("whatever/absolute/or/relative", "../")
// "whatever/absolute/or/" (POSIX)
// "whatever\\absolute\\or\\" (Windows)
```
```javascript
require("path").join(".", "../")
// "../" (POSIX)
// "..\\" (Windows)
```
```javascript
require("path").join("..", "../")
// "../../" (POSIX)
// "..\\..\\" (Windows)
```
```javascript
require("path").win32.join("C:\\", "../")
// "C:\\"
```

use [path.dirname](

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// onlyPath should be G:\node-demos\7-handlebars-watch\demo
var onlyPath = require('path').dirname('G:\\node-demos\\7-node-module\\demo\\config.json');

Simply install `path` module and use it,

var path = require('path');
path.dirname('G:\\node-demos\\7-node-module\\demo\\config.json')

// Returns: 'G:\node-demos\7-node-module\demo'