Running 7-Zip from within a Powershell script

I'm trying to use 7-Zip to backup some files inside a Powershell (v2) script.

I have:

$zipPath = "C:\Program Files\7-Zip\7z.exe"
[Array]$zipArgs = "-mx=9 a", "`"c:\BackupFolder\backup.zip`"", "`"c:\BackupFrom\backMeUp.txt`""

&$zipPath $zipArgs;

But when I run this I get:

7-Zip [64] 9.20 Copyright © 1999-2010 Igor Pavlov 2010-11-18


Error:
Incorrect command line

Writing this to the screen I get:

C:\Program Files\7-Zip\7z.exe -mx=9 a "c:\BackupFolder\backup.zip" "c:\BackupFrom\backMeUp.txt"

So I assumed that I needed to put quotes around the path to 7z.exe, that gave me:

$zipPath = "C:\Program Files\7-Zip\7z.exe"
$zipPath = " `"$zipPath`" "
[Array]$zipArgs = "-mx=9 a", "`"c:\BackupFolder\backup.zip`"", "`"c:\BackupFrom\backMeUp.txt`""

&$zipPath $zipArgs;

But then I get the following error:

The term '"C:\Program Files\7-Zip\7z.exe"' is not recognized as the name of a cmdlet, function, script file
, or operable program. Check the spelling of the name, or if a path was included, verify that the path is c
orrect and try again.
At C:\BackupScript\Backup.ps1:45 char:22
+ & <<<< `"$zipPath`" $zipArgs;
+ CategoryInfo : ObjectNotFound: ("C:\Program Files\7-Zip\7z.exe":String) [], CommandNotFound
Exception
+ FullyQualifiedErrorId : CommandNotFoundException

Writing it out gives me:

"C:\Program Files\7-Zip\7z.exe" -mx=9 a "c:\BackupFolder\backup.zip" "c:\BackupFrom\backMeUp.txt"


Which works as expected when pasting straight into a command window.
I have been trying to figure this out for a while, but assume I am missing something (probably quite obvious). Can anybody see what I need to do to make this run?

Maybe a simpler solution is to run 7-zip on your Powershell via `cmd`:

cmd /c 7za ...

put "&" special character before 7z command. Example: &7z ...

try to use parameter -file to specify the location of program or script:

-file "C:\Program Files\someting.exe"

Simply prefix the command with an ampersand

& "C:\Program Files\7-Zip\7z.exe" -mx=9 a "c:\BackupFolder\backup.zip" "c:\BackupFrom\backMeUp.txt"

If you adapt it correctly: Dont forget the "" on "$Target"
and avoid $7zipPath in c:\programm files with a space in the path

Set-Alias 7zip $7zipPath

$Source = "c:\BackupFrom\backMeUp.txt"
$Target = "c:\BackupFolder\backup.zip"

7zip a -mx=9 "$Target" "$Source"

or

7z a "$ArchiveName" -t7z '@listfile.txt'

C:\'Program files'\7-Zip\7z.exe a '$archiveFile' -Path '$dest'

where:

* `archiveFile` = name of the archive file name.
* `dest` = destination folder.

Found [this][1] script and adapted it to your needs. Can you please try:

```powershell
$7zipPath = "$env:ProgramFiles\7-Zip\7z.exe"

if (-not (Test-Path -Path $7zipPath -PathType Leaf)) {
throw "7 zip file '$7zipPath' not found"
}

Set-Alias Start-SevenZip $7zipPath

$Source = "c:\BackupFrom\backMeUp.txt"
$Target = "c:\BackupFolder\backup.zip"

Start-SevenZip a -mx=9 $Target $Source
```

[1]:

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