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+--- Thread: passing path to SqlCmd within powershell script (/Thread-passing-path-to-SqlCmd-within-powershell-script)
passing path to SqlCmd within powershell script - judgements320107 - 07-21-2023
I'm trying to write a powershell script which will execute sqlcmd.exe to run a sql script. The script contains a SQLCMD variable which I want to pass in on the command line via sqlcmd's -v switch. The problem is that powershell is doing something weird when I pass a path as the value of one of my variables which in turn causes the SQL script to fail.
For example I'm calling:
$path = 'C:\path'
sqlcmd -SMySQLServerInstance -i 'MySqlScript.sql' -v MyVariablePath=$path
when run I receive a error which says:
Sqlcmd: ':\path': Invalid argument.
No amount of double or single quotes that I have tried around `$path` or `MyVariablePath=$path`
solves the issue.
Can somebody provide a simple canonical example of how this needs to be done?
RE: passing path to SqlCmd within powershell script - Mrsoucy0 - 07-21-2023
You will find several options to this issue on the Workarounds tab on [this issue filed on the Microsoft connect site][1]. While you're there please vote it up.
[1]:
[To see links please register here]
RE: passing path to SqlCmd within powershell script - obedience197 - 07-21-2023
finally worked it out. for the next sucker to try this here is the solution
powershell script looks like
$myPath = "`"C:\Path`""
sqlcmd.exe -SmySQLInstance -i./test.sql -v myvar=$myPath
my test.sql file can then use the variable like this
PRINT "$(myvar)"
the key here is understanding how powershell does escape characters. More info on that [here][1]
[1]:
[To see links please register here]
RE: passing path to SqlCmd within powershell script - Sirour184 - 07-21-2023
Had the same issue, found the solution accidentally, still don't understand why it works :) (i'm not a powershell pro though):
sqlcmd -d ... -s ... -v Var1Name=("""$PowershellVar1""") Var2Name=("""$PowershellVar2""")
Variables `$PowershellVar1` and `$PowershellVar2` have string type in my PS script and can contain quotes, spaces etc
RE: passing path to SqlCmd within powershell script - anchovettas468199 - 07-21-2023
I was recently playing around with this problem. In my case, I had variables with dots and spaces inside them. I will list all combinations I tried to make it run.
### Test SQL file test.sql ###
declare @testvar varchar(30);
set @testvar = '$(testvar)';
print @testvar;
### Set of my testing variables: ###
$varA = 'Abc1.3,Abc4.3' # contains only dots
$varB = 'A bc1.3,Ab c4.3' # contains dots and spaces
$varC = 'xx x.yy,y,.1.2.,3 , y' # contains dots and multiple spaces
### Testing of **sqlcmd** command ###
sqlcmd -v testvar=`"$var`" -i test.sql
sqlcmd -v testvar=($var) -i test.sql
sqlcmd -v testvar=("""$var""") -i test.sql # Solution by Andrei Shakh
## a) Test #1 ##
First I found out that my powershell script is returning error on variable that contain spaces
sqlcmd -v testvar=`"$varA`" -i test.sql
Abc1.3,Abc4.3
sqlcmd -v testvar=`"$varB`" -i test.sql
sqlcmd : Sqlcmd: 'testvar="A bc1.3,Ab c4.3""': Invalid argument. Enter '-?' for help. At line:2 char:1
## b) Test #2 ##
Finally found solution to replace variable by parenthesis instead of double-quotes, BUT!
sqlcmd -v testvar=($varA) -i test.sql
sqlcmd : Sqlcmd: ',Abc4.3': Invalid argument. Enter '-?' for help. At line:1 char:1
sqlcmd -v testvar=($varB) -i test.sql
A bc1.3,Ab c4.3
Interestingly enough, I've found out that this solution isn't working with with dots in my variables.
## c) Test #3 ##
I made a script to match space in variable and in that case use parenthesis, which works both ways.
If ($var -match " ") # or ($var -like "* *")
{
sqlcmd -v testvar=($var) -i test.sql
}
Else
{
sqlcmd -v testvar=`"$var`" -i test.sql
}
# d) Final Solution #
So far best solution I've found was answer by [Andrei Shakh](
[To see links please register here]
) here, which works with everything without using IF/ELSE statemens to check whether there is space in a string or not.sqlcmd -v testvar=("""$varA""") -i test.sql
Abc1.3,Abc4.3
sqlcmd -v testvar=("""$varB""") -i test.sql
A bc1.3,Ab c4.3
sqlcmd -v testvar=("""$varC""") -i test.sql
xx x.yy,y,.1.2.,3 , y